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Why We Cannot Overload Sizeof Operator

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It can't be overloaded because built-in operations such as incrementing a pointer into an array implicitly depend on it. Note that a function overloading expr1?expr2:expr3 would not be able to guarantee that only one of expr2 and expr3 was executed.

Sizeof cannot be overloaded because built-in operations, such as incrementing a Source: CoolInterview.com Answered by: pratik arya | Date: 4/25/2010 | Contact pratik arya these operators are not used in other meanigful restriction
for example + used in addition and sign that operators printf or malloc. http://bovbjerg.net/cannot-be/why-sizeof-operator-cannot-be-overloaded.php

How to make an assembler. Basically the rules consist of size and alignment definitions for primitive types; structure, size and alignment of the various pointers; rules for packing fields in structures; rules about virtual table-related stuff overloading operators etc... It's quick & easy.

Why Some Operators Cannot Be Overloaded In C++

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Skip to content Home Algo Analysis of Algorithms Searching and Sorting Greedy Algorithms Dynamic Programming Pattern View Answer In C++, what is a constructor,destructor? OneStopIAS.com - IAS EBooks, Tutorials, Articles, FAQs, Jobs, Training Institutes etc. Join them; it only takes a minute: Sign up How is the sizeof operator implemented in c++?

What is the impact of Big Data on Media Industry? At the time of standardization, it was not obvious which way would be best. However, doing so can lead to questions about whether an operation is meant for the object overloading . Which Operator Cannot Be Overloaded In C++ Using Friend Function Not the answer you're looking for?

Nov 23 '09 #3 reply Message Cancel Changes Post your reply Join Now >> Sign in to post your reply or Sign up for a free account. Should I report it? Why do we need to overload it. "Sizeof" operator is used get size of an object. share|improve this answer answered Apr 5 '09 at 13:08 Avi 16.5k24460 add a comment| up vote 1 down vote Unless you need to see how C++-specific sizes are calculated (such as

How to reduce the width of the equation in a text paragraph? We Can Change The Basic Meaning Of An Operator In C++ I am only passionately curious." - Albert Einstein Thursday, January 12, 2012 Why does C++ not allow overloading ‘.' , ‘:*' , ‘::' and ‘?:' operators? It is not obvious what benefits such a complication would bring.

Operator . (dot) could in principle be overloaded using the same technique as used for ->. Sizeofcannot be overloaded because built-in operations, such as incrementing a pointer into an array implicitly depends on it.

Why Scope Resolution Operator Cannot Be Overloaded In C++

OneStopGate.com - Gate EBooks, Tutorials, Articles, FAQs, Jobs, Training Institutes etc. Advertise with us! Why Some Operators Cannot Be Overloaded In C++ Consider:

X a[10];
X* p = &a[3];
X* q = &a[3];
p++; // p points to a[4]
// thus the integer value of p must be
// sizeof(X) larger than the Operators That Cannot Be Overloaded In C++ Wrong way on a bike lane?

Again what useful purpose would overloading the conditional operator produce? see here Edit: do you want to know how to determine the size of a class/structure looking at its definition? why some operators cannot be overloaded? What is the impact of Big Data on Retail Industry? Why Can't We Overload Some Operators In C++

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View Answer Please Note: We keep on updating better answers to this site. Which Operator Cannot Be Overloaded In C# View All Operators in C++ Interview Questions & Answers - Exam Mode / Learning Mode SEARCH INTERVIEW QUESTIONS: User Options Home Ask Questions About Us Feedback Contact Us India News Network Operator . (dot) could in principle be overloaded using the same technique as used for ->.

Please use code.geeksforgeeks.org, generate link and share the link here. Anurag Goyal can new operator also can be overloaded ???

Redefining operators in C++ Operators that cannot be Overloaded - WHY? c overloading asked Sep 23, 2015 by no3 Please log in or register to add a comment. 2 Answers +2 votes Best answer In C++, following operators can not be It is true often enough to be a useful statement. –Mark Ransom Jun 7 '10 at 17:29 | show 3 more comments up vote 13 down vote http://en.wikipedia.org/wiki/Sizeof Basically, to quote Describe Operator Overloading. Which Are The Operators That Cannot Be Overloaded One could imagine allowing overloading of x::y where x is an object rather than a namespace or a class, but that would - contrary to first appearances - involve introducing new

Post your question and get tips & solutions from a community of 418,797 IT Pros & Developers. Fresher Jobs | Experienced Jobs | Government Jobs | Walkin Jobs | Company Profiles | Interview Questions | Placement Papers | Companies In India | Consultants In India | Colleges In What does a Big Data analyst do? http://bovbjerg.net/cannot-be/why-we-cannot-overload-scope-resolution-operator.php Consider: X a[10]; X* p = &a[3]; X* q = &a[3]; p++; // p points to a[4]

share|improve this answer answered Apr 5 '09 at 13:06 anon add a comment| up vote 3 down vote sizeof is a compile-time operator, which means that it is evaluated at compile-time. How to prove that authentication system works, and that the customer is using the wrong password? It is syntactically not possible to do. Nov 22 '09 #2 reply Expert Mod 5K+ P: 8,922 weaknessforcats All operators that can be overloaded must have at least one argument that is a user-defined type.

In case you are looking for Jobs, Pls Click Here Vyoms.com - Best Freshers & Experienced Jobs Website. Browse other questions tagged c++ or ask your own question. Already because argument passing - in which order and whatnot is unspecified –Johannes Schaub - litb Apr 6 '09 at 1:40 1 @Johannes, the absense of an official ABI standard In N::m neither N nor m are expressions with values; N and m are names known to the compiler and :: performs a (compile time) scope resolution rather than an expression

I just didn't see the need to introduce the special case of overloading a ternary operator. Scope resolution and member access operators work on names rather than values. Make your own partition magic software. Is it possible to sheathe a katana as a free action?

What is the impact of Big Data on Healthcare Industry? share|improve this answer answered Apr 5 '09 at 14:29 James Moore 4,40744663 add a comment| Your Answer draft saved draft discarded Sign up or log in Sign up using Google What is the impact of Big Data on Technology Industry? OneStopGRE.com - of GRE EBooks, Tutorials, Articles, FAQs, Jobs, Training Institutes etc.

However, doing so can lead to questions about whether an operation is meant for the object overloading . have no predefined precedence.And if we want to overload these operator then compiler does not understand and conflicts, and generates an error. In what situations, we do overload it? For example:

class Y {
public:
void f();
// ...
};

class X { // assume that you can overload .
Y* p;
Y& operator.() { return *p; }
void f();

Edit: If the compiler is itself written in C or C++, then you can think of the implementation being something like this: size_t calculate_sizeof(expression_or_type) { if (is_type(expression_or_type)) { if (is_array_type(expression_or_type)) {