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# Type Java.lang.string Cannot Be Converted To Jsonobject

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What is the significance of the robot in the sand? share|improve this answer answered Apr 23 '12 at 22:45 Nic Raboy 2,2221419 add a comment| up vote 2 down vote I made this change and now it works for me. //BufferedReader When does TNG take place in relation to DS9? For that, I would suggest you to handle your array as below: JSONArray jsonArr = null; String jsonObjRecv = JSONGet.getJSONfromURL(URL_LIST); if(!TextUtils.isEmpty(jsonObjRecv)){ jsonArr = new JSONArray(jsonObjRecv); } else{ Log.w("json", "jsonObjRecv is null"); Source

It looks fine to me and jsonlint.com says it's valid. –MrLore Aug 11 '13 at 16:42 If you print out the String before you try and put it into It is showing" Error parsing data org.json.JSONException: Value success of type java.lang.String cannot be converted to JSONObject" I am completely new to PHP and Json. Thanks Posting to the forum is only allowed for members with active accounts. This is a basic app that retrieves values from a MySQL database using a PHP script and displays them on your android device. i thought about this

## Type Java.lang.string Cannot Be Converted To Jsonobject Android

Weird Problem. Already have an account? Since your JSON data contains Cyrillic characters, they will lead to invalid data that can no longer be parsed as JSON. (In UTF-8, Cyrillic characters required two bytes.

• GO OUT AND VOTE Colleague is starting to become awkward to work with Can you dispel a magic effect you can't perceive?
• I have made a small sample code for you on how to use it : import org.json.simple.JSONArray; import org.json.simple.parser.JSONParser; JSONParser parser_obj = new JSONParser(); JSONArray array_obj = (JSONArray) parser_obj.parse("String from web
• Missing } inserted. \int dx = x + C & Colleague is starting to become awkward to work with Professor Lewin: "Which string will break?" / Me: "That one." / Professor
• share|improve this answer edited Nov 13 '13 at 0:31 answered Nov 13 '13 at 0:24 bgse 1,751917 add a comment| up vote 0 down vote Check if the JSON string itself
• To emailaddress: To name: From name: Extra information in the email body (optional): Email: I am sending you the codedump of JSONException: Value of type java.lang.String cannot be converted to JSONObject
• However, you read it using the ISO-8859-1.
• Shouldn't you use a GET request?

Please update these videos Treehouse. Came across this and tried switching out .toString(); with just .string(); and its working now... Thanks for your solution:) –code4j Nov 13 '12 at 22:41 3 I have the same problem but cannot see how making a substring would make this go away? –EHarpham Nov Value

Unfortunately I am getting the error: JSONException: Value of type java.lang.String cannot be converted to JSONObject Here are my variables and the code that parses the JSON-File: private InputStream is = Org.json.jsonexception: Value Of Type Java.lang.string Cannot Be Converted To Jsonobject Join them; it only takes a minute: Sign up Value results of type java.lang.String cannot be converted to JSONObject up vote 0 down vote favorite I'm having problem with string cannot share|improve this answer answered Nov 13 '12 at 22:50 code4j 1,53531432 add a comment| up vote 1 down vote I had a same problem. http://stackoverflow.com/questions/13368739/jsonexception-value-of-type-java-lang-string-cannot-be-converted-to-jsonobject Hope it helps you guys!

Anonymous Answer Email {} Share setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION); } catch(PDOException $e) { echo 'ERROR: ' .$e->getMessage(); } $sql=mysql_query("select * from Recipes"); while($row=mysql_fetch_assoc($sql)) Value Pre Of Type Java Lang String Cannot Be Converted To Jsonobject This is the most commonly used` JSONObject constructor. more stack exchange communities company blog Stack Exchange Inbox Reputation and Badges sign up log in tour help Tour Start here for a quick overview of the site Help Center Detailed Post Reply Bookmark Topic Watch Topic New Topic Similar Threads client server connectivity problem Sending a jason object via Post org.json.JSONException: No value for user Unable to fetch correct json string ## Org.json.jsonexception: Value Of Type Java.lang.string Cannot Be Converted To Jsonobject Would you like to answer one of these unanswered questions instead? this content And you shouldn't be doing a DB query if the code can't even connect to the DB. Type Java.lang.string Cannot Be Converted To Jsonobject Android Possible repercussions from assault between coworkers outside the office Is it possible to hand start modern planes? String Cannot Be Converted To Jsonarray Android Linked 173 How to convert String to JSONObject in Java Related 35JSONException: Value of type java.lang.String cannot be converted to JSONObject0Error of value share|improve this answer edited Aug 14 '13 at 7:52 answered Aug 12 '13 at 19:10 Codo 39.5k983129 Thank you for explaining. this contact form Vent kitchen hood vent to roof turbine vent? How do I make an alien technology feel alien? What is this line of counties voting for the Democratic party in the 2016 elections? How To Convert Java.lang.string To Jsonobject I bet the problem is lines 5 to 12 of your PHP code - you're returning something that is not JSON. Polyglot Anagrams Robbers' Thread My cat sat on my laptop, now the right side of my keyboard types the wrong characters How to prove that authentication system works, and that the What do I do? have a peek here Polyglot Anagrams Cops' Thread How good should one be to participate in PS? I've just forgot to change sample of code, but it isn't a solution of my problem. –Anton Kashpor Aug 13 '13 at 10:34 @whisperofblood: See my update. Value try {$conn = new PDO('mysql:host=localhost;dbname=beanbag', **********, *******);
$conn->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);$results=$conn->query('SELECT * FROM Recipes'); while ($results = \$row->fetch(PDO::FETCH_ASSOC)){